四川省雅安市2015-2016学年高一下期末数学试卷含答案解析  
7．已知正方体ABCD﹣A1B1C1D1，则过点A与AB、BC、CC1所成角均相等的直线有（　　）                
A．1条       B．2条       C．4条        D．无数条
【分析】先确定直线和AB，BC所成角相等的直线在对角面内，然后确定在对角面内的体对角线满足条件．分别进行类比寻找即可．                                                                                                          
【解答】解：若直线和AB，BC所成角相等，得直线在对角面BDD1B1，内或者和对角面平行，同时和CC1所成角相等，此时在对角面内只有体对角线BD1满足条件．此时过A的直线和BD1，平行即可，                 
同理体对角线A1C，AC1，DB1，也满足条件．，                                                     
则过点A与AB、BC、CC1所成角均相等的直线只要和四条体对角线平行即可，           
共有4条．                                                                                                          
故选：C．